Public Sub GetDetails( _
   ByVal id As Integer, _
   ByVal onCompleted As Action(Of FeatureLayerInfo,Exception) _
) 

public void GetDetails( 
   int id,
   Action<FeatureLayerInfo,Exception> onCompleted
)

<Grid x:Name="LayoutRoot">
  
  <!-- Add a Map Control. Set the Extent to that of the Great Lakes region. -->
  <esri:Map Background="White" HorizontalAlignment="Left" Margin="6,227,0,0" Name="Map1" Height="361" 
            VerticalAlignment="Top" Width="616" Extent="-10726306,4955978,-8152376,6464401">
  
    <!-- 
    Add an ArcGISTiledMapServiceLayer. Wire up the Initialized Event to display the sub-layer ID's in the Listbox.
    -->
    <esri:ArcGISTiledMapServiceLayer ID="Soil_Survey_Map"
          Url="http://server.arcgisonline.com/ArcGIS/rest/services/Specialty/Soil_Survey_Map/MapServer" 
          Initialized="ArcGISTiledMapServiceLayer_Initialized" />
    
  </esri:Map>
  
  <!-- Display the sub-layer Name when the user clicks any of the Buttons. -->
  <sdk:Label Height="19" HorizontalAlignment="Left" Margin="11,192,0,0" Name="Label_SubLayerName" 
       VerticalAlignment="Top" Width="100" Content="Sub-Layer Name:"/>
  <TextBox Height="23" HorizontalAlignment="Left" Margin="117,188,0,0" Name="TextBox_SubLayerName" 
           VerticalAlignment="Top" Width="505" />
  
  <!-- Have the user choose a sub-layer ID from the ListBox. -->
  <TextBlock Text="Pick a sub-layer ID and Click one of the buttons:" TextWrapping="Wrap" Margin="625,227,97,260" />
  <ListBox Height="143" HorizontalAlignment="Left" Margin="625,296,0,0" Name="ListBox_SubLayerID" 
           VerticalAlignment="Top" Width="78" />
  
  <!-- 
  Each of the four Buttons uses the ArcGISTiledMapServiceLayer.GetDetails Method to display the sub-layer Name
  in the TextBox. Each button uses a slightly different coding methadology but accompolishes the same result.
  -->
  <Button Content="Option1" Height="23" HorizontalAlignment="Left" Margin="625,445,0,0" Name="Button1" 
          VerticalAlignment="Top" Width="75" Click="Button1_Click"/>
  <Button Content="Option2" Height="23" HorizontalAlignment="Left" Margin="627,479,0,0" Name="Button2" 
          VerticalAlignment="Top" Width="75" Click="Button2_Click"/>
  <Button Content="Option3" Height="23" HorizontalAlignment="Left" Margin="628,514,0,0" Name="Button3" 
          VerticalAlignment="Top" Width="75" Click="Button3_Click" />
  <Button Content="Option4" Height="23" HorizontalAlignment="Left" Margin="628,548,0,0" Name="Button4" 
          VerticalAlignment="Top" Width="75" Click="Button4_Click"/>
  
  <!-- Provide the instructions on how to use the sample code. -->
  <TextBlock Height="102" HorizontalAlignment="Left" Name="TextBlock1" VerticalAlignment="Top" Width="622" 
             TextWrapping="Wrap" Text="When the application loads an ArcGISTiledMapServiceLayer will display 
             and the sub-layer ID's will be shown in the ListBox. Choose a sub-layer ID and then click one of 
             the four Buttons to display the sub-layer Name that was obtained via the 
             ArcGISTiledMapServiceLayer.GetDetails Method. Each of the four Buttons uses a slightly different 
             coding practice to achieve the same results." />
    
</Grid>

private void ArcGISTiledMapServiceLayer_Initialized(object sender, System.EventArgs e)
{
  // Get the ArcGISTiledMapServiceLayer.
  ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer myArcGISTiledMapServiceLayer = null;
  myArcGISTiledMapServiceLayer = (ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer)sender;
  
  // Get the collection of LayerInfo objects
  ESRI.ArcGIS.Client.LayerInfo[] myLayerInfos = myArcGISTiledMapServiceLayer.Layers;
  
  // Loop throgh each LayerInfo object and display the sub-layer ID value in the ListBox.
  foreach (ESRI.ArcGIS.Client.LayerInfo myLayerInfo in myLayerInfos)
  {
    ListBox_SubLayerID.Items.Add(myLayerInfo.ID);
  }
  
  // If we have more than one sub-layer ID, select the first one as the default.
  if (myLayerInfos.Count() > 0)
  {
    ListBox_SubLayerID.SelectedIndex = 0;
  }
}
  
// IMPORTANT NOTE:
// Each of the four options below accompolish the same result of using the ArcGISTiledMapServiceLayer.GetDetails 
// Method to display a sub-layer Name in the TextBox. The various options are shown to demonstrate different
// coding styles you may want to consider using. Options #1 and #2 are beneficial for small bits of code. 
// The external sub-routine options (#3 and #4) are better when the coding algorithms get longer and more 
// complicated.
  
#region Option1: in-line lambda version
  private void Button1_Click(object sender, System.Windows.RoutedEventArgs e)
  {
    // Clear out any prior sub-layer ID text value.
    TextBox_SubLayerName.Text = "";
    
    // Get the ArcGISTiledMapServiceLayer.
    ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer myArcGISTiledMapServiceLayer = null;
    myArcGISTiledMapServiceLayer = (ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer)(Map1.Layers["Soil_Survey_Map"]);
    
    // Get the user selected sub-layer ID value.
    int mySubLayerID = (int)ListBox_SubLayerID.SelectedValue;
    
    // Use a lambda expression for the ArcGISTiledMapServiceLayer.GetDetails Method to display the sub-layer Name in the TextBox.
    myArcGISTiledMapServiceLayer.GetDetails(mySubLayerID, (ESRI.ArcGIS.Client.FeatureService.FeatureLayerInfo myFeatureLayerInfo, Exception myException) =>
    {
      if (myException == null)
      {
        TextBox_SubLayerName.Text = myFeatureLayerInfo.Name;
      }
    });
  }
#endregion
            
#region Option2: Action version
  private void Button2_Click(object sender, System.Windows.RoutedEventArgs e)
  {
    // Clear out any prior sub-layer ID text value.
    TextBox_SubLayerName.Text = "";
    
    // Get the ArcGISTiledMapServiceLayer.
    ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer myArcGISTiledMapServiceLayer = null;
    myArcGISTiledMapServiceLayer = (ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer)(Map1.Layers["Soil_Survey_Map"]);
    
    // Define an Action to handle the work of the ArcGISTiledMapServiceLayer.GetDetails Method to display the sub-layer Name in the TextBox.
    Action<ESRI.ArcGIS.Client.FeatureService.FeatureLayerInfo, Exception> myAction = (myFeatureLayerInfo, myException) =>
    {
      if (myException == null)
      {
        TextBox_SubLayerName.Text = myFeatureLayerInfo.Name;
      }
    };
    
    // Get the user selected sub-layer ID value.
    int mySubLayerID = (int)ListBox_SubLayerID.SelectedValue;
    
    // Invoke the ArcGISTiledMapServiceLayer.GetDetails Method, which will use the Action.
    myArcGISTiledMapServiceLayer.GetDetails(mySubLayerID, myAction);
  }
#endregion
            
#region Option3: external function call version
  private void Button3_Click(object sender, System.Windows.RoutedEventArgs e)
  {
    // Clear out any prior sub-layer ID text value.
    TextBox_SubLayerName.Text = "";
    
    // Get the ArcGISTiledMapServiceLayer.
    ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer myArcGISTiledMapServiceLayer = null;
    myArcGISTiledMapServiceLayer = (ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer)(Map1.Layers["Soil_Survey_Map"]);
    
    // Get the user selected sub-layer ID value.
    int mySubLayerID = (int)ListBox_SubLayerID.SelectedValue;
    
    // Invoke the ArcGISTiledMapServiceLayer.GetDetails Method, which will use an external sub-routine via AddressOf. 
    myArcGISTiledMapServiceLayer.GetDetails(mySubLayerID, ShowName);
  }
  
  private void ShowName(ESRI.ArcGIS.Client.FeatureService.FeatureLayerInfo myFeatureLayerInfo, Exception myException)
  {
    // Display the sub-layer Name in the TextBox.
    if (myException == null)
    {
      TextBox_SubLayerName.Text = myFeatureLayerInfo.Name;
    }
  }
#endregion
            
#region Option4: external function call via Action version
  
  private void Button4_Click(object sender, System.Windows.RoutedEventArgs e)
  {
    // Clear out any prior sub-layer ID text value.
    TextBox_SubLayerName.Text = "";
    
    // Get the ArcGISTiledMapServiceLayer.
    ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer myArcGISTiledMapServiceLayer = null;
    myArcGISTiledMapServiceLayer = (ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer)(Map1.Layers["Soil_Survey_Map"]);
    
    // Define an Action to handle the work of the ArcGISTiledMapServiceLayer.GetDetails Method to display the sub-layer Name in the TextBox.
    Action<ESRI.ArcGIS.Client.FeatureService.FeatureLayerInfo, Exception> myAction = ShowName2;
    
    // Get the user selected sub-layer ID value.
    int mySubLayerID = (int)ListBox_SubLayerID.SelectedValue;
    
    // Invoke the ArcGISTiledMapServiceLayer.GetDetails Method, which will use the Action.
    myArcGISTiledMapServiceLayer.GetDetails(mySubLayerID, myAction);
  }
  
  private void ShowName2(ESRI.ArcGIS.Client.FeatureService.FeatureLayerInfo myFeatureLayerInfo, Exception myException)
  {
    // Display the sub-layer Name in the TextBox.
    if (myException == null)
    {
      TextBox_SubLayerName.Text = myFeatureLayerInfo.Name;
    }
  }
  
#endregion

Private Sub ArcGISTiledMapServiceLayer_Initialized(ByVal sender As System.Object, ByVal e As System.EventArgs)
  
  ' Get the ArcGISTiledMapServiceLayer.
  Dim myArcGISTiledMapServiceLayer As ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer
  myArcGISTiledMapServiceLayer = CType(sender, ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer)
  
  ' Get the collection of LayerInfo objects
  Dim myLayerInfos As ESRI.ArcGIS.Client.LayerInfo() = myArcGISTiledMapServiceLayer.Layers
  
  ' Loop throgh each LayerInfo object and display the sub-layer ID value in the ListBox.
  For Each myLayerInfo As ESRI.ArcGIS.Client.LayerInfo In myLayerInfos
    ListBox_SubLayerID.Items.Add(myLayerInfo.ID)
  Next
  
  ' If we have more than one sub-layer ID, select the first one as the default.
  If myLayerInfos.Count > 0 Then
    ListBox_SubLayerID.SelectedIndex = 0
  End If
  
End Sub
            
' IMPORTANT NOTE:
' Each of the four options below accompolish the same result of using the ArcGISTiledMapServiceLayer.GetDetails 
' Method to display a sub-layer Name in the TextBox. The various options are shown to demonstrate different
' coding styles you may want to consider using. Options #1 and #2 are beneficial for small bits of code. 
' The external sub-routine options (#3 and #4) are better when the coding algorithms get longer and more 
' complicated.
            
#Region "Option1: in-line lambda version"
            
  Private Sub Button1_Click(sender As System.Object, e As System.Windows.RoutedEventArgs)
  
    ' Clear out any prior sub-layer ID text value.
    TextBox_SubLayerName.Text = ""
    
    ' Get the ArcGISTiledMapServiceLayer.
    Dim myArcGISTiledMapServiceLayer As ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer
    myArcGISTiledMapServiceLayer = CType(Map1.Layers("Soil_Survey_Map"), ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer)
    
    ' Get the user selected sub-layer ID value.
    Dim mySubLayerID As Integer = ListBox_SubLayerID.SelectedValue
    
    ' Use a lambda expression for the ArcGISTiledMapServiceLayer.GetDetails Method to display the sub-layer Name in the TextBox.
    myArcGISTiledMapServiceLayer.GetDetails(mySubLayerID, Sub(myFeatureLayerInfo As ESRI.ArcGIS.Client.FeatureService.FeatureLayerInfo, myException As Exception)
                                                            If myException Is Nothing Then
                                                              TextBox_SubLayerName.Text = myFeatureLayerInfo.Name
                                                            End If
                                                          End Sub)
    
  End Sub
  
#End Region
            
#Region "Option2: Action version"
            
  Private Sub Button2_Click(sender As System.Object, e As System.Windows.RoutedEventArgs)
    
    ' Clear out any prior sub-layer ID text value.
    TextBox_SubLayerName.Text = ""
    
    ' Get the ArcGISTiledMapServiceLayer.
    Dim myArcGISTiledMapServiceLayer As ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer = Nothing
    myArcGISTiledMapServiceLayer = CType(Map1.Layers("Soil_Survey_Map"), ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer)
    
    ' Define an Action to handle the work of the ArcGISTiledMapServiceLayer.GetDetails Method to display the sub-layer Name in the TextBox.
    Dim myAction As Action(Of ESRI.ArcGIS.Client.FeatureService.FeatureLayerInfo, Exception) = Sub(myFeatureLayerInfo, myException)
                                                                                                 If myException Is Nothing Then
                                                                                                   TextBox_SubLayerName.Text = myFeatureLayerInfo.Name
                                                                                                 End If
                                                                                               End Sub
    
    ' Get the user selected sub-layer ID value.
    Dim mySubLayerID As Integer = ListBox_SubLayerID.SelectedValue
    
    ' Invoke the ArcGISTiledMapServiceLayer.GetDetails Method, which will use the Action.
    myArcGISTiledMapServiceLayer.GetDetails(mySubLayerID, myAction)
    
  End Sub
  
#End Region
            
#Region "Option3: external function call via Addressof version"
  
  Private Sub Button3_Click(sender As System.Object, e As System.Windows.RoutedEventArgs)
    
    ' Clear out any prior sub-layer ID text value.
    TextBox_SubLayerName.Text = ""
    
    ' Get the ArcGISTiledMapServiceLayer.
    Dim myArcGISTiledMapServiceLayer As ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer
    myArcGISTiledMapServiceLayer = CType(Map1.Layers("Soil_Survey_Map"), ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer)
    
    ' Get the user selected sub-layer ID value.
    Dim mySubLayerID As Integer = ListBox_SubLayerID.SelectedValue
    
    ' Invoke the ArcGISTiledMapServiceLayer.GetDetails Method, which will use an external sub-routine via AddressOf. 
    myArcGISTiledMapServiceLayer.GetDetails(mySubLayerID, AddressOf ShowName)
    
  End Sub
  
  Private Sub ShowName(myFeatureLayerInfo As ESRI.ArcGIS.Client.FeatureService.FeatureLayerInfo, myException As Exception)
    
    ' Display the sub-layer Name in the TextBox.
    If myException Is Nothing Then
      TextBox_SubLayerName.Text = myFeatureLayerInfo.Name
    End If
    
  End Sub
  
#End Region
            
#Region "Option4: external function call via Action Addressof version"
  
  Private Sub Button4_Click(sender As System.Object, e As System.Windows.RoutedEventArgs)
    
    ' Clear out any prior sub-layer ID text value.
    TextBox_SubLayerName.Text = ""
    
    ' Get the ArcGISTiledMapServiceLayer.
    Dim myArcGISTiledMapServiceLayer As ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer
    myArcGISTiledMapServiceLayer = CType(Map1.Layers("Soil_Survey_Map"), ESRI.ArcGIS.Client.ArcGISTiledMapServiceLayer)
    
    ' Define an Action to handle the work of the ArcGISTiledMapServiceLayer.GetDetails Method to display the sub-layer Name in the TextBox.
    Dim myAction As Action(Of ESRI.ArcGIS.Client.FeatureService.FeatureLayerInfo, Exception) = AddressOf ShowName2
    
    ' Get the user selected sub-layer ID value.
    Dim mySubLayerID As Integer = ListBox_SubLayerID.SelectedValue
    
    ' Invoke the ArcGISTiledMapServiceLayer.GetDetails Method, which will use the Action.
    myArcGISTiledMapServiceLayer.GetDetails(mySubLayerID, myAction)
    
  End Sub
  
  Private Sub ShowName2(myFeatureLayerInfo As ESRI.ArcGIS.Client.FeatureService.FeatureLayerInfo, myException As Exception)
    
    ' Display the sub-layer Name in the TextBox.
    If myException Is Nothing Then
      TextBox_SubLayerName.Text = myFeatureLayerInfo.Name
    End If
  
  End Sub
  
#End Region